13331243311411 has 4 divisors (see below), whose sum is σ = 13331279396872. Its totient is φ = 13331207225952.

The previous prime is 13331243311343. The next prime is 13331243311469. The reversal of 13331243311411 is 11411334213331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331243311411 - 2²¹ = 13331241214259 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331243317411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17482785 + ... + 18229378.

It is an arithmetic number, because the mean of its divisors is an integer number (3332819849218).

Almost surely, 2^{13331243311411} is an apocalyptic number.

13331243311411 is a deficient number, since it is larger than the sum of its proper divisors (36085461).

13331243311411 is an equidigital number, since it uses as much as digits as its factorization.

13331243311411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36085460.

The product of its digits is 7776, while the sum is 31.

Adding to 13331243311411 its reverse (11411334213331), we get a palindrome (24742577524742).

The spelling of 13331243311411 in words is "thirteen trillion, three hundred thirty-one billion, two hundred forty-three million, three hundred eleven thousand, four hundred eleven".