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13331432003 = 61721606859
BaseRepresentation
bin11000110101001110…
…11000001001000011
31021102002102220200212
430122213120021003
5204300321311003
610042510504335
7651236205461
oct143247301103
937362386625
1013331432003
1157212781aa
1227008050ab
131345c56506
149067a1831
155305bddd8
hex31a9d8243

13331432003 has 4 divisors (see below), whose sum is σ = 13353039480. Its totient is φ = 13309824528.

The previous prime is 13331431991. The next prime is 13331432047. The reversal of 13331432003 is 30023413331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331432003 - 24 = 13331431987 is a prime.

It is a super-2 number, since 2×133314320032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13331432003.

It is not an unprimeable number, because it can be changed into a prime (13331432083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10802813 + ... + 10804046.

It is an arithmetic number, because the mean of its divisors is an integer number (3338259870).

Almost surely, 213331432003 is an apocalyptic number.

13331432003 is a deficient number, since it is larger than the sum of its proper divisors (21607477).

13331432003 is an equidigital number, since it uses as much as digits as its factorization.

13331432003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21607476.

The product of its (nonzero) digits is 1944, while the sum is 23.

Adding to 13331432003 its reverse (30023413331), we get a palindrome (43354845334).

The spelling of 13331432003 in words is "thirteen billion, three hundred thirty-one million, four hundred thirty-two thousand, three".

Divisors: 1 617 21606859 13331432003