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13331688240803 = 101811309467463
BaseRepresentation
bin1100001000000000011010…
…0010101011011010100011
31202012111102021102222101212
43002000012202223122203
53221411244142201203
644204254254420335
72544116443210532
oct302000642533243
952174367388355
1013331688240803
11427aa34501359
1215b392b5016ab
1375923286c16a
143413858b6319
15181bc3c9e1d8
hexc20068ab6a3

13331688240803 has 4 divisors (see below), whose sum is σ = 13332997718448. Its totient is φ = 13330378763160.

The previous prime is 13331688240779. The next prime is 13331688240889. The reversal of 13331688240803 is 30804288613331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331688240803 - 218 = 13331687978659 is a prime.

It is a super-2 number, since 2×133316882408032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13331688243803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 654723551 + ... + 654743912.

It is an arithmetic number, because the mean of its divisors is an integer number (3333249429612).

Almost surely, 213331688240803 is an apocalyptic number.

13331688240803 is a deficient number, since it is larger than the sum of its proper divisors (1309477645).

13331688240803 is a wasteful number, since it uses less digits than its factorization.

13331688240803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1309477644.

The product of its (nonzero) digits is 1990656, while the sum is 50.

The spelling of 13331688240803 in words is "thirteen trillion, three hundred thirty-one billion, six hundred eighty-eight million, two hundred forty thousand, eight hundred three".

Divisors: 1 10181 1309467463 13331688240803