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133320222001 = 465128664851
BaseRepresentation
bin111110000101010000…
…0010010010100110001
3110202010022111222222001
41330022200102110301
54141014434101001
6141125123014001
712426541121611
oct1741240222461
9422108458861
10133320222001
11515a487605a
1221a0880a301
13c758a17335
14664a42aa41
1537045ad001
hex1f0a812531

133320222001 has 4 divisors (see below), whose sum is σ = 133348891504. Its totient is φ = 133291552500.

The previous prime is 133320221989. The next prime is 133320222019. The reversal of 133320222001 is 100222023331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133320222001 - 27 = 133320221873 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133320222001.

It is not an unprimeable number, because it can be changed into a prime (133320225001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14327775 + ... + 14337076.

It is an arithmetic number, because the mean of its divisors is an integer number (33337222876).

Almost surely, 2133320222001 is an apocalyptic number.

It is an amenable number.

133320222001 is a deficient number, since it is larger than the sum of its proper divisors (28669503).

133320222001 is an equidigital number, since it uses as much as digits as its factorization.

133320222001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28669502.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 133320222001 its reverse (100222023331), we get a palindrome (233542245332).

The spelling of 133320222001 in words is "one hundred thirty-three billion, three hundred twenty million, two hundred twenty-two thousand, one".

Divisors: 1 4651 28664851 133320222001