Base | Representation |
---|---|
bin | 11110010100000101111001… |
… | …000001101001101001100011 |
3 | 122111001110200002122202200212 |
4 | 132110011321001221221203 |
5 | 114433322140214423021 |
6 | 1151315155411204335 |
7 | 40040130115345316 |
oct | 3624057101515143 |
9 | 574043602582625 |
10 | 133322110311011 |
11 | 39531653630106 |
12 | 12b52874ba66ab |
13 | 59512b487974b |
14 | 24ccb7889097d |
15 | 106303261985b |
hex | 794179069a63 |
133322110311011 has 4 divisors (see below), whose sum is σ = 133341104777400. Its totient is φ = 133303115844624.
The previous prime is 133322110310971. The next prime is 133322110311017. The reversal of 133322110311011 is 110113011223331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133322110311011 - 238 = 133047232404067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133322110311017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9497222666 + ... + 9497236703.
It is an arithmetic number, because the mean of its divisors is an integer number (33335276194350).
Almost surely, 2133322110311011 is an apocalyptic number.
133322110311011 is a deficient number, since it is larger than the sum of its proper divisors (18994466389).
133322110311011 is an equidigital number, since it uses as much as digits as its factorization.
133322110311011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18994466388.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 133322110311011 its reverse (110113011223331), we get a palindrome (243435121534342).
The spelling of 133322110311011 in words is "one hundred thirty-three trillion, three hundred twenty-two billion, one hundred ten million, three hundred eleven thousand, eleven".
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