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1333240113 = 31729901447
BaseRepresentation
bin100111101110111…
…1010000100110001
310102220201121121110
41033131322010301
510212302140423
6340143543533
745016232262
oct11735720461
93386647543
101333240113
11624641037
123125baba9
131832a599a
14c90d4969
157c0a9193
hex4f77a131

1333240113 has 16 divisors (see below), whose sum is σ = 1947127680. Its totient is φ = 807695616.

The previous prime is 1333240109. The next prime is 1333240123. The reversal of 1333240113 is 3110423331.

It is not a de Polignac number, because 1333240113 - 22 = 1333240109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1333240113.

It is not an unprimeable number, because it can be changed into a prime (1333240123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 449245 + ... + 452202.

It is an arithmetic number, because the mean of its divisors is an integer number (121695480).

Almost surely, 21333240113 is an apocalyptic number.

It is an amenable number.

1333240113 is a deficient number, since it is larger than the sum of its proper divisors (613887567).

1333240113 is a wasteful number, since it uses less digits than its factorization.

1333240113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 901496.

The product of its (nonzero) digits is 648, while the sum is 21.

The square root of 1333240113 is about 36513.5606727145. The cubic root of 1333240113 is about 1100.6167651372.

Adding to 1333240113 its reverse (3110423331), we get a palindrome (4443663444).

The spelling of 1333240113 in words is "one billion, three hundred thirty-three million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 3 17 29 51 87 493 1479 901447 2704341 15324599 26141963 45973797 78425889 444413371 1333240113