1333311102113 has 4 divisors (see below), whose sum is σ = 1333353770688. Its totient is φ = 1333268433540.

The previous prime is 1333311102107. The next prime is 1333311102131. The reversal of 1333311102113 is 3112011133331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1333311102113 - 2⁶ = 1333311102049 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1333311102313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21287381 + ... + 21349922.

It is an arithmetic number, because the mean of its divisors is an integer number (333338442672).

Almost surely, 2^{1333311102113} is an apocalyptic number.

It is an amenable number.

1333311102113 is a deficient number, since it is larger than the sum of its proper divisors (42668575).

1333311102113 is an equidigital number, since it uses as much as digits as its factorization.

1333311102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42668574.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1333311102113 its reverse (3112011133331), we get a palindrome (4445322235444).

The spelling of 1333311102113 in words is "one trillion, three hundred thirty-three billion, three hundred eleven million, one hundred two thousand, one hundred thirteen".