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133332013001 = 1112121092091
BaseRepresentation
bin111110000101100110…
…1010000111111001001
3110202011010201001011202
41330023031100333021
54141030443404001
6141130223433545
712430043260655
oct1741315207711
9422133631152
10133332013001
1151600499890
1221a107558b5
13c75b2b5165
14664bc19a65
15370563b96b
hex1f0b350fc9

133332013001 has 4 divisors (see below), whose sum is σ = 145453105104. Its totient is φ = 121210920900.

The previous prime is 133332012949. The next prime is 133332013033. The reversal of 133332013001 is 100310233331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133332013001 - 214 = 133331996617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133332010001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6060546035 + ... + 6060546056.

It is an arithmetic number, because the mean of its divisors is an integer number (36363276276).

Almost surely, 2133332013001 is an apocalyptic number.

133332013001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

133332013001 is a deficient number, since it is larger than the sum of its proper divisors (12121092103).

133332013001 is a wasteful number, since it uses less digits than its factorization.

133332013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12121092102.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 133332013001 its reverse (100310233331), we get a palindrome (233642246332).

The spelling of 133332013001 in words is "one hundred thirty-three billion, three hundred thirty-two million, thirteen thousand, one".

Divisors: 1 11 12121092091 133332013001