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1333422440401 = 10990311213271
BaseRepresentation
bin10011011001110110001…
…010111011111111010001
311201110210111120100020011
4103121312022323333101
5133321322121043101
62500322114314521
7165223310506522
oct23316612737721
94643714510204
101333422440401
11474557229367
12196514588a41
13989835414ac
1448776362849
1524a4323a751
hex136762bbfd1

1333422440401 has 4 divisors (see below), whose sum is σ = 1333424752704. Its totient is φ = 1333420128100.

The previous prime is 1333422440377. The next prime is 1333422440411. The reversal of 1333422440401 is 1040442243331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1333422440401 - 25 = 1333422440369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1333422440411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 492396 + ... + 1705666.

It is an arithmetic number, because the mean of its divisors is an integer number (333356188176).

Almost surely, 21333422440401 is an apocalyptic number.

It is an amenable number.

1333422440401 is a deficient number, since it is larger than the sum of its proper divisors (2312303).

1333422440401 is a wasteful number, since it uses less digits than its factorization.

1333422440401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2312302.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1333422440401 its reverse (1040442243331), we get a palindrome (2373864683732).

The spelling of 1333422440401 in words is "one trillion, three hundred thirty-three billion, four hundred twenty-two million, four hundred forty thousand, four hundred one".

Divisors: 1 1099031 1213271 1333422440401