Base | Representation |
---|---|
bin | 1100001000001110100111… |
… | …0100100010110110101001 |
3 | 1202012212021000111010002212 |
4 | 3002003221310202312221 |
5 | 3221442101321233421 |
6 | 44210124510534505 |
7 | 2544313104136046 |
oct | 302035164426651 |
9 | 52185230433085 |
10 | 13335501352361 |
11 | 4281610948521 |
12 | 15b4614507435 |
13 | 7596bc8474a6 |
14 | 34162809c1cd |
15 | 181d48909e5b |
hex | c20e9d22da9 |
13335501352361 has 4 divisors (see below), whose sum is σ = 13645629290832. Its totient is φ = 13025373413892.
The previous prime is 13335501352343. The next prime is 13335501352363. The reversal of 13335501352361 is 16325310553331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13335501352361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13335501352363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155063969171 + ... + 155063969256.
It is an arithmetic number, because the mean of its divisors is an integer number (3411407322708).
Almost surely, 213335501352361 is an apocalyptic number.
It is an amenable number.
13335501352361 is a deficient number, since it is larger than the sum of its proper divisors (310127938471).
13335501352361 is an equidigital number, since it uses as much as digits as its factorization.
13335501352361 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 310127938470.
The product of its (nonzero) digits is 364500, while the sum is 41.
The spelling of 13335501352361 in words is "thirteen trillion, three hundred thirty-five billion, five hundred one million, three hundred fifty-two thousand, three hundred sixty-one".
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