Base | Representation |
---|---|
bin | 10011011010011000101… |
… | …010011001010000110001 |
3 | 11201112021211102220120210 |
4 | 103122120222121100301 |
5 | 133324013241041423 |
6 | 2500455345254333 |
7 | 165243535235205 |
oct | 23323052312061 |
9 | 4645254386523 |
10 | 1334001112113 |
11 | 474823939a4a |
12 | 1966563343a9 |
13 | 98a463b01a7 |
14 | 487cd156b05 |
15 | 24a78e43b93 |
hex | 13698a99431 |
1334001112113 has 8 divisors (see below), whose sum is σ = 1778703718176. Its totient is φ = 889316290400.
The previous prime is 1334001112079. The next prime is 1334001112139. The reversal of 1334001112113 is 3112111004331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1334001112113 - 228 = 1333732676657 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1334001112113.
It is not an unprimeable number, because it can be changed into a prime (1334001112313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4270068 + ... + 4571813.
It is an arithmetic number, because the mean of its divisors is an integer number (222337964772).
Almost surely, 21334001112113 is an apocalyptic number.
It is an amenable number.
1334001112113 is a deficient number, since it is larger than the sum of its proper divisors (444702606063).
1334001112113 is an equidigital number, since it uses as much as digits as its factorization.
1334001112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8892175.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1334001112113 its reverse (3112111004331), we get a palindrome (4446112116444).
The spelling of 1334001112113 in words is "one trillion, three hundred thirty-four billion, one million, one hundred twelve thousand, one hundred thirteen".
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