Base | Representation |
---|---|
bin | 11000110110010000… |
… | …01001111001110011 |
3 | 1021102200121110022002 |
4 | 30123020021321303 |
5 | 204310021240220 |
6 | 10043415004215 |
7 | 651402223343 |
oct | 143310117163 |
9 | 37380543262 |
10 | 13340024435 |
11 | 5726106891 |
12 | 270366966b |
13 | 13479744aa |
14 | 90799ad23 |
15 | 531219c75 |
hex | 31b209e73 |
13340024435 has 8 divisors (see below), whose sum is σ = 16187895360. Its totient is φ = 10552108864.
The previous prime is 13340024419. The next prime is 13340024459. The reversal of 13340024435 is 53442004331.
13340024435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13340024435 - 24 = 13340024419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13340024398 and 13340024407.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14988347 + ... + 14989236.
It is an arithmetic number, because the mean of its divisors is an integer number (2023486920).
Almost surely, 213340024435 is an apocalyptic number.
13340024435 is a deficient number, since it is larger than the sum of its proper divisors (2847870925).
13340024435 is an equidigital number, since it uses as much as digits as its factorization.
13340024435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29977677.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 13340024435 its reverse (53442004331), we get a palindrome (66782028766).
The spelling of 13340024435 in words is "thirteen billion, three hundred forty million, twenty-four thousand, four hundred thirty-five".
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