Base | Representation |
---|---|
bin | 10011011010011001110… |
… | …011110000101001010011 |
3 | 11201112100011122000022211 |
4 | 103122121303300221103 |
5 | 133324033202010103 |
6 | 2500501313412551 |
7 | 165244160556055 |
oct | 23323163605123 |
9 | 4645304560284 |
10 | 1334020344403 |
11 | 4748337854aa |
12 | 19666086a157 |
13 | 98a4a385046 |
14 | 487d19218d5 |
15 | 24a7a99236d |
hex | 13699cf0a53 |
1334020344403 has 8 divisors (see below), whose sum is σ = 1357072496640. Its totient is φ = 1311060586440.
The previous prime is 1334020344347. The next prime is 1334020344409. The reversal of 1334020344403 is 3044430204331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1334020344403 is a prime.
It is a super-2 number, since 2×13340203444032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1334020344409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23069443 + ... + 23127196.
It is an arithmetic number, because the mean of its divisors is an integer number (169634062080).
Almost surely, 21334020344403 is an apocalyptic number.
1334020344403 is a deficient number, since it is larger than the sum of its proper divisors (23052152237).
1334020344403 is an equidigital number, since it uses as much as digits as its factorization.
1334020344403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46197137.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 1334020344403 its reverse (3044430204331), we get a palindrome (4378450548734).
The spelling of 1334020344403 in words is "one trillion, three hundred thirty-four billion, twenty million, three hundred forty-four thousand, four hundred three".
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