133402420444153 has 4 divisors (see below), whose sum is σ = 152459909079040. Its totient is φ = 114344931809268.

The previous prime is 133402420444121. The next prime is 133402420444187. The reversal of 133402420444153 is 351444024204331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133402420444153 - 2⁵ = 133402420444121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133402426444153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9528744317433 + ... + 9528744317446.

It is an arithmetic number, because the mean of its divisors is an integer number (38114977269760).

Almost surely, 2^{133402420444153} is an apocalyptic number.

It is an amenable number.

133402420444153 is a deficient number, since it is larger than the sum of its proper divisors (19057488634887).

133402420444153 is an equidigital number, since it uses as much as digits as its factorization.

133402420444153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19057488634886.

The product of its (nonzero) digits is 552960, while the sum is 40.

Adding to 133402420444153 its reverse (351444024204331), we get a palindrome (484846444648484).

The spelling of 133402420444153 in words is "one hundred thirty-three trillion, four hundred two billion, four hundred twenty million, four hundred forty-four thousand, one hundred fifty-three".