13340342420243 has 4 divisors (see below), whose sum is σ = 13650582941688. Its totient is φ = 13030101898800.

The previous prime is 13340342420231. The next prime is 13340342420261. The reversal of 13340342420243 is 34202424304331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13340342420243 - 2¹⁴ = 13340342403859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13340342420203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155120260658 + ... + 155120260743.

It is an arithmetic number, because the mean of its divisors is an integer number (3412645735422).

Almost surely, 2^{13340342420243} is an apocalyptic number.

13340342420243 is a deficient number, since it is larger than the sum of its proper divisors (310240521445).

13340342420243 is an equidigital number, since it uses as much as digits as its factorization.

13340342420243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 310240521444.

The product of its (nonzero) digits is 165888, while the sum is 35.

Adding to 13340342420243 its reverse (34202424304331), we get a palindrome (47542766724574).

The spelling of 13340342420243 in words is "thirteen trillion, three hundred forty billion, three hundred forty-two million, four hundred twenty thousand, two hundred forty-three".