133404030001201 has 4 divisors (see below), whose sum is σ = 133404056701812. Its totient is φ = 133404003300592.

The previous prime is 133404030001141. The next prime is 133404030001213. The reversal of 133404030001201 is 102100030404331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 72463524527601 + 60940505473600 = 8512551^2 + 7806440^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133404030001201 is a prime.

It is a super-2 number, since 2×133404030001201² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133404030001601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3367750 + ... + 16677823.

It is an arithmetic number, because the mean of its divisors is an integer number (33351014175453).

Almost surely, 2^{133404030001201} is an apocalyptic number.

It is an amenable number.

133404030001201 is a deficient number, since it is larger than the sum of its proper divisors (26700611).

133404030001201 is an equidigital number, since it uses as much as digits as its factorization.

133404030001201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26700610.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 133404030001201 its reverse (102100030404331), we get a palindrome (235504060405532).

The spelling of 133404030001201 in words is "one hundred thirty-three trillion, four hundred four billion, thirty million, one thousand, two hundred one".