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1334104014331 = 11260718164173
BaseRepresentation
bin10011011010011110110…
…010111011110111111011
311201112120000001212220001
4103122132302323313323
5133324221111424311
62500513503013431
7165246225005524
oct23323662736773
94645500055801
101334104014331
11474876a32a00
1219668489a277
1398a617cb98a
14487dcaa184b
1524a82ebd4c1
hex1369ecbbdfb

1334104014331 has 12 divisors (see below), whose sum is σ = 1468827766336. Its totient is φ = 1210823705520.

The previous prime is 1334104014317. The next prime is 1334104014343.

1334104014331 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1334104014331 - 27 = 1334104014203 is a prime.

It is a super-2 number, since 2×13341040143312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1334104014331.

It is not an unprimeable number, because it can be changed into a prime (1334104014301) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9008640 + ... + 9155533.

Almost surely, 21334104014331 is an apocalyptic number.

1334104014331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1334104014331 is a deficient number, since it is larger than the sum of its proper divisors (134723752005).

1334104014331 is a wasteful number, since it uses less digits than its factorization.

1334104014331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18164802 (or 18164791 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

The spelling of 1334104014331 in words is "one trillion, three hundred thirty-four billion, one hundred four million, fourteen thousand, three hundred thirty-one".

Divisors: 1 11 121 607 6677 73447 18164173 199805903 2197864933 11025653011 121282183121 1334104014331