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13341054403 = 121071101929
BaseRepresentation
bin11000110110011000…
…00101010111000011
31021102202112210011001
430123030011113003
5204310302220103
610043453032431
7651414043225
oct143314052703
937382483131
1013341054403
11572674a6a6
122703a85717
131347c45241
14907b88415
1553137001d
hex31b3055c3

13341054403 has 4 divisors (see below), whose sum is σ = 13342168440. Its totient is φ = 13339940368.

The previous prime is 13341054379. The next prime is 13341054409. The reversal of 13341054403 is 30445014331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13341054403 - 221 = 13338957251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13341054409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 538858 + ... + 563071.

It is an arithmetic number, because the mean of its divisors is an integer number (3335542110).

Almost surely, 213341054403 is an apocalyptic number.

13341054403 is a deficient number, since it is larger than the sum of its proper divisors (1114037).

13341054403 is a wasteful number, since it uses less digits than its factorization.

13341054403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1114036.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13341054403 its reverse (30445014331), we get a palindrome (43786068734).

The spelling of 13341054403 in words is "thirteen billion, three hundred forty-one million, fifty-four thousand, four hundred three".

Divisors: 1 12107 1101929 13341054403