Search a number
-
+
133414040403 = 3272117683181
BaseRepresentation
bin111110001000000011…
…0001011001101010011
3110202100212001110121200
41330100012023031103
54141212443243103
6141142313522243
712432060426630
oct1742006131523
9422325043550
10133414040403
1151642825226
1221a34113383
13c7722a5297
146658a8d187
15370c9410a3
hex1f1018b353

133414040403 has 12 divisors (see below), whose sum is σ = 220239050928. Its totient is φ = 76236594480.

The previous prime is 133414040401. The next prime is 133414040411. The reversal of 133414040403 is 304040414331.

It is not a de Polignac number, because 133414040403 - 21 = 133414040401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (133414040401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1058841528 + ... + 1058841653.

It is an arithmetic number, because the mean of its divisors is an integer number (18353254244).

Almost surely, 2133414040403 is an apocalyptic number.

133414040403 is a deficient number, since it is larger than the sum of its proper divisors (86825010525).

133414040403 is a wasteful number, since it uses less digits than its factorization.

133414040403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2117683194 (or 2117683191 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 133414040403 its reverse (304040414331), we get a palindrome (437454454734).

The spelling of 133414040403 in words is "one hundred thirty-three billion, four hundred fourteen million, forty thousand, four hundred three".

Divisors: 1 3 7 9 21 63 2117683181 6353049543 14823782267 19059148629 44471346801 133414040403