Base | Representation |
---|---|
bin | 11000110110011010… |
… | …11101001110111011 |
3 | 1021102210020001212201 |
4 | 30123031131032323 |
5 | 204310400224311 |
6 | 10043504451031 |
7 | 651420102460 |
oct | 143315351673 |
9 | 37383201781 |
10 | 13341414331 |
11 | 5726976063 |
12 | 2704019a77 |
13 | 134804000b |
14 | 907c3d667 |
15 | 5313e19c1 |
hex | 31b35d3bb |
13341414331 has 4 divisors (see below), whose sum is σ = 15247330672. Its totient is φ = 11435497992.
The previous prime is 13341414299. The next prime is 13341414397.
13341414331 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13341414331 - 25 = 13341414299 is a prime.
It is a super-2 number, since 2×133414143312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13341414331.
It is not an unprimeable number, because it can be changed into a prime (13341414131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 952958160 + ... + 952958173.
It is an arithmetic number, because the mean of its divisors is an integer number (3811832668).
Almost surely, 213341414331 is an apocalyptic number.
13341414331 is a deficient number, since it is larger than the sum of its proper divisors (1905916341).
13341414331 is an equidigital number, since it uses as much as digits as its factorization.
13341414331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1905916340.
The product of its digits is 5184, while the sum is 28.
The spelling of 13341414331 in words is "thirteen billion, three hundred forty-one million, four hundred fourteen thousand, three hundred thirty-one".
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