Base | Representation |
---|---|
bin | 10011011010100010100… |
… | …001101111000100111011 |
3 | 11201112201100212021221120 |
4 | 103122202201233010323 |
5 | 133324333123124311 |
6 | 2500524020440323 |
7 | 165250615052025 |
oct | 23324241570473 |
9 | 4645640767846 |
10 | 1334166614331 |
11 | 4748a92aa241 |
12 | 1966a18490a3 |
13 | 98a717791b5 |
14 | 48807119015 |
15 | 24a88736706 |
hex | 136a286f13b |
1334166614331 has 8 divisors (see below), whose sum is σ = 1781050291200. Its totient is φ = 888363673512.
The previous prime is 1334166614279. The next prime is 1334166614387.
1334166614331 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1334166614331 - 215 = 1334166581563 is a prime.
It is a super-2 number, since 2×13341666143312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1334166614531) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 270181131 + ... + 270186068.
It is an arithmetic number, because the mean of its divisors is an integer number (222631286400).
Almost surely, 21334166614331 is an apocalyptic number.
1334166614331 is a deficient number, since it is larger than the sum of its proper divisors (446883676869).
1334166614331 is an equidigital number, since it uses as much as digits as its factorization.
1334166614331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 540368025.
The product of its digits is 279936, while the sum is 42.
The spelling of 1334166614331 in words is "one trillion, three hundred thirty-four billion, one hundred sixty-six million, six hundred fourteen thousand, three hundred thirty-one".
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