13342132221403 has 4 divisors (see below), whose sum is σ = 14044349706760. Its totient is φ = 12639914736048.

The previous prime is 13342132221391. The next prime is 13342132221449. The reversal of 13342132221403 is 30412223124331.

13342132221403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13342132221403 is a prime.

It is a super-2 number, since 2×13342132221403² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13342132021403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351108742650 + ... + 351108742687.

It is an arithmetic number, because the mean of its divisors is an integer number (3511087426690).

Almost surely, 2^{13342132221403} is an apocalyptic number.

13342132221403 is a deficient number, since it is larger than the sum of its proper divisors (702217485357).

13342132221403 is an equidigital number, since it uses as much as digits as its factorization.

13342132221403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 702217485356.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13342132221403 its reverse (30412223124331), we get a palindrome (43754355345734).

The spelling of 13342132221403 in words is "thirteen trillion, three hundred forty-two billion, one hundred thirty-two million, two hundred twenty-one thousand, four hundred three".