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13342344312201 = 34447448104067
BaseRepresentation
bin1100001000101000000110…
…1100010111010110001001
31202020111220220201111021220
43002022001230113112021
53222100110120442301
644213215515152253
72544644505264222
oct302120154272611
952214826644256
1013342344312201
114284502591533
1215b5a04145689
1375a240457c58
14341ab6c1a249
151820e9553936
hexc2281b17589

13342344312201 has 4 divisors (see below), whose sum is σ = 17789792416272. Its totient is φ = 8894896208132.

The previous prime is 13342344312181. The next prime is 13342344312263. The reversal of 13342344312201 is 10221344324331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13342344312201 - 221 = 13342342215049 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13342344312301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223724052031 + ... + 2223724052036.

It is an arithmetic number, because the mean of its divisors is an integer number (4447448104068).

Almost surely, 213342344312201 is an apocalyptic number.

It is an amenable number.

13342344312201 is a deficient number, since it is larger than the sum of its proper divisors (4447448104071).

13342344312201 is an equidigital number, since it uses as much as digits as its factorization.

13342344312201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4447448104070.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13342344312201 its reverse (10221344324331), we get a palindrome (23563688636532).

The spelling of 13342344312201 in words is "thirteen trillion, three hundred forty-two billion, three hundred forty-four million, three hundred twelve thousand, two hundred one".

Divisors: 1 3 4447448104067 13342344312201