13342421010433 has 4 divisors (see below), whose sum is σ = 13342753588528. Its totient is φ = 13342088432340.

The previous prime is 13342421010409. The next prime is 13342421010437. The reversal of 13342421010433 is 33401012424331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13342421010433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13342421010395 and 13342421010404.

It is not an unprimeable number, because it can be changed into a prime (13342421010437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166228863 + ... + 166309108.

It is an arithmetic number, because the mean of its divisors is an integer number (3335688397132).

Almost surely, 2^{13342421010433} is an apocalyptic number.

It is an amenable number.

13342421010433 is a deficient number, since it is larger than the sum of its proper divisors (332578095).

13342421010433 is an equidigital number, since it uses as much as digits as its factorization.

13342421010433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 332578094.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 13342421010433 its reverse (33401012424331), we get a palindrome (46743433434764).

The spelling of 13342421010433 in words is "thirteen trillion, three hundred forty-two billion, four hundred twenty-one million, ten thousand, four hundred thirty-three".