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13343025035 = 541402116187
BaseRepresentation
bin11000110110100111…
…00110011110001011
31021102220020220100102
430123103212132023
5204311303300120
610044003200015
7651436561424
oct143323463613
937386226312
1013343025035
11572787621a
12270467600b
1313484851b2
1490813c64b
1553160dd75
hex31b4e678b

13343025035 has 16 divisors (see below), whose sum is σ = 16407250272. Its totient is φ = 10410835200.

The previous prime is 13343025011. The next prime is 13343025037. The reversal of 13343025035 is 53052034331.

It is not a de Polignac number, because 13343025035 - 218 = 13342762891 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13343024989 and 13343025007.

It is not an unprimeable number, because it can be changed into a prime (13343025037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 816212 + ... + 832398.

It is an arithmetic number, because the mean of its divisors is an integer number (1025453142).

Almost surely, 213343025035 is an apocalyptic number.

13343025035 is a deficient number, since it is larger than the sum of its proper divisors (3064225237).

13343025035 is a wasteful number, since it uses less digits than its factorization.

13343025035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20254.

The product of its (nonzero) digits is 16200, while the sum is 29.

Adding to 13343025035 its reverse (53052034331), we get a palindrome (66395059366).

The spelling of 13343025035 in words is "thirteen billion, three hundred forty-three million, twenty-five thousand, thirty-five".

Divisors: 1 5 41 205 4021 16187 20105 80935 164861 663667 824305 3318335 65087927 325439635 2668605007 13343025035