Base | Representation |
---|---|
bin | 10011011010101100010… |
… | …110011001010111111011 |
3 | 11201120010211221222121102 |
4 | 103122230112121113323 |
5 | 133330202320222021 |
6 | 2500552225002015 |
7 | 165254655611411 |
oct | 23325426312773 |
9 | 4646124858542 |
10 | 1334331414011 |
11 | 47498332a722 |
12 | 196728a8330b |
13 | 98a9995a4bb |
14 | 48820d772b1 |
15 | 24a97e3b00b |
hex | 136ac5995fb |
1334331414011 has 4 divisors (see below), whose sum is σ = 1335980773800. Its totient is φ = 1332682054224.
The previous prime is 1334331414007. The next prime is 1334331414113. The reversal of 1334331414011 is 1104141334331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1334331414011 - 22 = 1334331414007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1334391414011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 824678681 + ... + 824680298.
It is an arithmetic number, because the mean of its divisors is an integer number (333995193450).
Almost surely, 21334331414011 is an apocalyptic number.
1334331414011 is a deficient number, since it is larger than the sum of its proper divisors (1649359789).
1334331414011 is an equidigital number, since it uses as much as digits as its factorization.
1334331414011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1649359788.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 1334331414011 its reverse (1104141334331), we get a palindrome (2438472748342).
The spelling of 1334331414011 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, four hundred fourteen thousand, eleven".
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