133433401001 has 4 divisors (see below), whose sum is σ = 140456211600. Its totient is φ = 126410590404.

The previous prime is 133433400949. The next prime is 133433401019. The reversal of 133433401001 is 100104334331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133433401001 - 2²² = 133429206697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133433401021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3511405271 + ... + 3511405308.

It is an arithmetic number, because the mean of its divisors is an integer number (35114052900).

Almost surely, 2^133433401001 is an apocalyptic number.

It is an amenable number.

133433401001 is a deficient number, since it is larger than the sum of its proper divisors (7022810599).

133433401001 is an equidigital number, since it uses as much as digits as its factorization.

133433401001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7022810598.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 133433401001 its reverse (100104334331), we get a palindrome (233537735332).

The spelling of 133433401001 in words is "one hundred thirty-three billion, four hundred thirty-three million, four hundred one thousand, one".