133440240441113 has 8 divisors (see below), whose sum is σ = 133612872282120. Its totient is φ = 133267673036160.

The previous prime is 133440240441077. The next prime is 133440240441121. The reversal of 133440240441113 is 311144042044331.

It can be written as a sum of positive squares in 4 ways, for example, as 3249912064 + 133436990529049 = 57008^2 + 11551493^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133440240441113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133040240441113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11963858 + ... + 20248811.

It is an arithmetic number, because the mean of its divisors is an integer number (16701609035265).

Almost surely, 2^{133440240441113} is an apocalyptic number.

It is an amenable number.

133440240441113 is a deficient number, since it is larger than the sum of its proper divisors (172631841007).

133440240441113 is an equidigital number, since it uses as much as digits as its factorization.

133440240441113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32218027.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 133440240441113 its reverse (311144042044331), we get a palindrome (444584282485444).

The spelling of 133440240441113 in words is "one hundred thirty-three trillion, four hundred forty billion, two hundred forty million, four hundred forty-one thousand, one hundred thirteen".