Base | Representation |
---|---|
bin | 1100001000110010011011… |
… | …0111101111100010111001 |
3 | 1202020210002001021020001112 |
4 | 3002030212313233202321 |
5 | 3222121244034114140 |
6 | 44214354512130105 |
7 | 2545103255300453 |
oct | 302144667574271 |
9 | 52223061236045 |
10 | 13345115535545 |
11 | 42856a48a4662 |
12 | 15b6458236935 |
13 | 75a59261ac91 |
14 | 341c9acad2d3 |
15 | 18220c9a6c65 |
hex | c2326def8b9 |
13345115535545 has 8 divisors (see below), whose sum is σ = 16014182025600. Its totient is φ = 10676063506480.
The previous prime is 13345115535527. The next prime is 13345115535571. The reversal of 13345115535545 is 54553551154331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13345115535545 - 26 = 13345115535481 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13345115535493 and 13345115535502.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1469195 + ... + 5371104.
It is an arithmetic number, because the mean of its divisors is an integer number (2001772753200).
Almost surely, 213345115535545 is an apocalyptic number.
It is an amenable number.
13345115535545 is a deficient number, since it is larger than the sum of its proper divisors (2669066490055).
13345115535545 is an equidigital number, since it uses as much as digits as its factorization.
13345115535545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7230495.
The product of its digits is 6750000, while the sum is 50.
Adding to 13345115535545 its reverse (54553551154331), we get a palindrome (67898666689876).
The spelling of 13345115535545 in words is "thirteen trillion, three hundred forty-five billion, one hundred fifteen million, five hundred thirty-five thousand, five hundred forty-five".
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