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13345825603 = 1110985313049
BaseRepresentation
bin11000110110111100…
…10010001101000011
31021110002112012000011
430123132102031003
5204313012404403
610044143205351
7651502434355
oct143336221503
937402465004
1013345825603
115729409340
1227055a6857
131348c25b36
1490866b0d5
155319b3a6d
hex31b792343

13345825603 has 16 divisors (see below), whose sum is σ = 14711004000. Its totient is φ = 12006247680.

The previous prime is 13345825529. The next prime is 13345825627. The reversal of 13345825603 is 30652854331.

13345825603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13345825603 - 225 = 13312271171 is a prime.

It is a super-2 number, since 2×133458256032 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13345826603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1016223 + ... + 1029271.

It is an arithmetic number, because the mean of its divisors is an integer number (919437750).

Almost surely, 213345825603 is an apocalyptic number.

13345825603 is a deficient number, since it is larger than the sum of its proper divisors (1365178397).

13345825603 is a wasteful number, since it uses less digits than its factorization.

13345825603 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14022.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 13345825603 in words is "thirteen billion, three hundred forty-five million, eight hundred twenty-five thousand, six hundred three".

Divisors: 1 11 109 853 1199 9383 13049 92977 143539 1022747 1422341 11130797 15645751 122438767 1213256873 13345825603