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13348125569147 = 19369161272379
BaseRepresentation
bin1100001000111101101001…
…0010000111000001111011
31202021001211211011202220112
43002033122102013001323
53222143430121203042
644220013315414535
72545240665202565
oct302173222070173
952231754152815
1013348125569147
1142869a9998436
1215b6b582b444b
1375a952106455
143420a4968335
15182336d7d982
hexc23da48707b

13348125569147 has 4 divisors (see below), whose sum is σ = 13417286841720. Its totient is φ = 13278964296576.

The previous prime is 13348125569137. The next prime is 13348125569173. The reversal of 13348125569147 is 74196552184331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13348125569147 - 28 = 13348125568891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13348125569137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34580635997 + ... + 34580636382.

It is an arithmetic number, because the mean of its divisors is an integer number (3354321710430).

Almost surely, 213348125569147 is an apocalyptic number.

13348125569147 is a deficient number, since it is larger than the sum of its proper divisors (69161272573).

13348125569147 is an equidigital number, since it uses as much as digits as its factorization.

13348125569147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69161272572.

The product of its digits is 21772800, while the sum is 59.

The spelling of 13348125569147 in words is "thirteen trillion, three hundred forty-eight billion, one hundred twenty-five million, five hundred sixty-nine thousand, one hundred forty-seven".

Divisors: 1 193 69161272379 13348125569147