Search a number
-
+
13349392875001 = 99559113408511
BaseRepresentation
bin1100001001000010010111…
…0100011111110111111001
31202021012010010211120201101
43002100211310133313321
53222204024034000001
644220343150251401
72545314254134051
oct302204564376771
952235103746641
1013349392875001
11428749a295047
1215b72507b6b61
1375aac4835081
14342184db8561
151823ad261a01
hexc2425d1fdf9

13349392875001 has 4 divisors (see below), whose sum is σ = 13349407279104. Its totient is φ = 13349378470900.

The previous prime is 13349392874977. The next prime is 13349392875037. The reversal of 13349392875001 is 10057829394331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13349392875001 - 211 = 13349392872953 is a prime.

It is a super-2 number, since 2×133493928750012 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13349392875101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5708665 + ... + 7699846.

It is an arithmetic number, because the mean of its divisors is an integer number (3337351819776).

Almost surely, 213349392875001 is an apocalyptic number.

It is an amenable number.

13349392875001 is a deficient number, since it is larger than the sum of its proper divisors (14404103).

13349392875001 is an equidigital number, since it uses as much as digits as its factorization.

13349392875001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14404102.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 13349392875001 in words is "thirteen trillion, three hundred forty-nine billion, three hundred ninety-two million, eight hundred seventy-five thousand, one".

Divisors: 1 995591 13408511 13349392875001