13349722081 has 4 divisors (see below), whose sum is σ = 13350355200. Its totient is φ = 13349088964.

The previous prime is 13349722049. The next prime is 13349722121. The reversal of 13349722081 is 18022794331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13349722081 - 2⁵ = 13349722049 is a prime.

It is a super-2 number, since 2×13349722081² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13349722021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283801 + ... + 327478.

It is an arithmetic number, because the mean of its divisors is an integer number (3337588800).

Almost surely, 2^13349722081 is an apocalyptic number.

It is an amenable number.

13349722081 is a deficient number, since it is larger than the sum of its proper divisors (633119).

13349722081 is an equidigital number, since it uses as much as digits as its factorization.

13349722081 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633118.

The product of its (nonzero) digits is 72576, while the sum is 40.

The spelling of 13349722081 in words is "thirteen billion, three hundred forty-nine million, seven hundred twenty-two thousand, eighty-one".