Base | Representation |
---|---|
bin | 111110001011001111… |
… | …0110010111001111011 |
3 | 110202122022121121000000 |
4 | 1330112132302321323 |
5 | 4141422404022010 |
6 | 141201101444043 |
7 | 12434531054256 |
oct | 1742636627173 |
9 | 422568547000 |
10 | 133521157755 |
11 | 51698238067 |
12 | 21a63b70623 |
13 | c78b53b52b |
14 | 6668db409d |
15 | 371704e7c0 |
hex | 1f167b2e7b |
133521157755 has 28 divisors (see below), whose sum is σ = 240228196560. Its totient is φ = 71211282192.
The previous prime is 133521157753. The next prime is 133521157793. The reversal of 133521157755 is 557751125331.
133521157755 is a `hidden beast` number, since 1 + 3 + 3 + 5 + 21 + 1 + 577 + 55 = 666.
It is not a de Polignac number, because 133521157755 - 21 = 133521157753 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 133521157755.
It is not an unprimeable number, because it can be changed into a prime (133521157753) by changing a digit.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 18312015 + ... + 18319304.
Almost surely, 2133521157755 is an apocalyptic number.
133521157755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133521157755 is a deficient number, since it is larger than the sum of its proper divisors (106707038805).
133521157755 is an frugal number, since it uses more digits than its factorization.
133521157755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36631342 (or 36631327 counting only the distinct ones).
The product of its digits is 551250, while the sum is 45.
The spelling of 133521157755 in words is "one hundred thirty-three billion, five hundred twenty-one million, one hundred fifty-seven thousand, seven hundred fifty-five".
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