Base | Representation |
---|---|
bin | 1100001001001100110101… |
… | …1101011110000000011011 |
3 | 1202021110101011010011212120 |
4 | 3002103031131132000123 |
5 | 3222230304041112311 |
6 | 44221530220512323 |
7 | 2545444045241364 |
oct | 302231535360033 |
9 | 52243334104776 |
10 | 13352205410331 |
11 | 4288702954507 |
12 | 15b78b66ab6a3 |
13 | 75b152430b68 |
14 | 342370742b6b |
15 | 1824c5125706 |
hex | c24cd75e01b |
13352205410331 has 16 divisors (see below), whose sum is σ = 17956598849280. Its totient is φ = 8824823834400.
The previous prime is 13352205410221. The next prime is 13352205410347. The reversal of 13352205410331 is 13301450225331.
It is not a de Polignac number, because 13352205410331 - 225 = 13352171855899 is a prime.
It is a super-3 number, since 3×133522054103313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 13352205410292 and 13352205410301.
It is not an unprimeable number, because it can be changed into a prime (13352205410371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22546255 + ... + 23130888.
It is an arithmetic number, because the mean of its divisors is an integer number (1122287428080).
Almost surely, 213352205410331 is an apocalyptic number.
13352205410331 is a deficient number, since it is larger than the sum of its proper divisors (4604393438949).
13352205410331 is a wasteful number, since it uses less digits than its factorization.
13352205410331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45677986.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13352205410331 its reverse (13301450225331), we get a palindrome (26653655635662).
The spelling of 13352205410331 in words is "thirteen trillion, three hundred fifty-two billion, two hundred five million, four hundred ten thousand, three hundred thirty-one".
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