Base | Representation |
---|---|
bin | 1100001001001101111100… |
… | …0001110010010000010011 |
3 | 1202021111010200201011020220 |
4 | 3002103133001302100103 |
5 | 3222231410014034443 |
6 | 44222015350004123 |
7 | 2545454254362561 |
oct | 302233701622023 |
9 | 52244120634226 |
10 | 13352500143123 |
11 | 4288844260629 |
12 | 15b7979346643 |
13 | 75b19b50636b |
14 | 34239b944a31 |
15 | 1824e0e43a83 |
hex | c24df072413 |
13352500143123 has 8 divisors (see below), whose sum is σ = 17881077339600. Its totient is φ = 8862794854368.
The previous prime is 13352500143121. The next prime is 13352500143161. The reversal of 13352500143123 is 32134100525331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13352500143123 - 21 = 13352500143121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13352500143121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9717976128 + ... + 9717977501.
It is an arithmetic number, because the mean of its divisors is an integer number (2235134667450).
Almost surely, 213352500143123 is an apocalyptic number.
13352500143123 is a deficient number, since it is larger than the sum of its proper divisors (4528577196477).
13352500143123 is a wasteful number, since it uses less digits than its factorization.
13352500143123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19435953861.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13352500143123 its reverse (32134100525331), we get a palindrome (45486600668454).
The spelling of 13352500143123 in words is "thirteen trillion, three hundred fifty-two billion, five hundred million, one hundred forty-three thousand, one hundred twenty-three".
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