Base | Representation |
---|---|
bin | 1100001001001110000100… |
… | …0001001100110100001001 |
3 | 1202021111020000120002220212 |
4 | 3002103201001030310021 |
5 | 3222231442041403301 |
6 | 44222022541530505 |
7 | 2545455141315035 |
oct | 302234101146411 |
9 | 52244200502825 |
10 | 13352533544201 |
11 | 42888610a4325 |
12 | 15b7988573a35 |
13 | 75b1a53cc407 |
14 | 3423a215b1c5 |
15 | 1824e3d404bb |
hex | c24e104cd09 |
13352533544201 has 4 divisors (see below), whose sum is σ = 14055298467600. Its totient is φ = 12649768620804.
The previous prime is 13352533544197. The next prime is 13352533544257. The reversal of 13352533544201 is 10244533525331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13352533544201 - 22 = 13352533544197 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13352533544281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351382461671 + ... + 351382461708.
It is an arithmetic number, because the mean of its divisors is an integer number (3513824616900).
Almost surely, 213352533544201 is an apocalyptic number.
It is an amenable number.
13352533544201 is a deficient number, since it is larger than the sum of its proper divisors (702764923399).
13352533544201 is an equidigital number, since it uses as much as digits as its factorization.
13352533544201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 702764923398.
The product of its (nonzero) digits is 648000, while the sum is 41.
The spelling of 13352533544201 in words is "thirteen trillion, three hundred fifty-two billion, five hundred thirty-three million, five hundred forty-four thousand, two hundred one".
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