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133525545434131 = 173771823962047
BaseRepresentation
bin11110010111000011010110…
…101101000011110000010011
3122111202220202211201210020111
4132113003112231003300103
5120000140304112343011
61151552442212022151
740060621330353454
oct3627032655036023
9574686684653214
10133525545434131
11395aa958437134
1212b8618b001957
13596753576b546
1424d8956c8312b
15106848c433121
hex7970d6b43c13

133525545434131 has 4 divisors (see below), whose sum is σ = 134297369396352. Its totient is φ = 132753721471912.

The previous prime is 133525545434119. The next prime is 133525545434159. The reversal of 133525545434131 is 131434545525331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133525545434131 - 233 = 133516955499539 is a prime.

It is a super-2 number, since 2×1335255454341312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133525545434191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385911980851 + ... + 385911981196.

It is an arithmetic number, because the mean of its divisors is an integer number (33574342349088).

Almost surely, 2133525545434131 is an apocalyptic number.

133525545434131 is a deficient number, since it is larger than the sum of its proper divisors (771823962221).

133525545434131 is an equidigital number, since it uses as much as digits as its factorization.

133525545434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 771823962220.

The product of its digits is 6480000, while the sum is 49.

The spelling of 133525545434131 in words is "one hundred thirty-three trillion, five hundred twenty-five billion, five hundred forty-five million, four hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 173 771823962047 133525545434131