Base | Representation |
---|---|
bin | 11110010111000011010110… |
… | …111111110010100000010011 |
3 | 122111202220210011222020121022 |
4 | 132113003112333302200103 |
5 | 120000140311342003321 |
6 | 1151552442505150055 |
7 | 40060621420163534 |
oct | 3627032677624023 |
9 | 574686704866538 |
10 | 133525550344211 |
11 | 395aa960190153 |
12 | 12b8619078b32b |
13 | 596753679a40c |
14 | 24d89577a068b |
15 | 106848caa2dab |
hex | 7970d6ff2813 |
133525550344211 has 4 divisors (see below), whose sum is σ = 133543552987512. Its totient is φ = 133507547700912.
The previous prime is 133525550344169. The next prime is 133525550344229. The reversal of 133525550344211 is 112443055525331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133525550344211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133525550344111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9001310525 + ... + 9001325358.
It is an arithmetic number, because the mean of its divisors is an integer number (33385888246878).
Almost surely, 2133525550344211 is an apocalyptic number.
133525550344211 is a deficient number, since it is larger than the sum of its proper divisors (18002643301).
133525550344211 is an equidigital number, since it uses as much as digits as its factorization.
133525550344211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18002643300.
The product of its (nonzero) digits is 1080000, while the sum is 44.
The spelling of 133525550344211 in words is "one hundred thirty-three trillion, five hundred twenty-five billion, five hundred fifty million, three hundred forty-four thousand, two hundred eleven".
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