Base | Representation |
---|---|
bin | 1100001001001111110011… |
… | …1101001001100000011001 |
3 | 1202021112102200111112100011 |
4 | 3002103330331021200121 |
5 | 3222233422033302441 |
6 | 44222141243441521 |
7 | 2545502562230101 |
oct | 302237475114031 |
9 | 52245380445304 |
10 | 13353002244121 |
11 | 4288a81722531 |
12 | 15b7a995262a1 |
13 | 75b24b545847 |
14 | 3424084c6201 |
15 | 182520074581 |
hex | c24fcf49819 |
13353002244121 has 4 divisors (see below), whose sum is σ = 13353085983952. Its totient is φ = 13352918504292.
The previous prime is 13353002244059. The next prime is 13353002244137. The reversal of 13353002244121 is 12144220035331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13353002244121 - 219 = 13353001719833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13353002244151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41630271 + ... + 41949796.
It is an arithmetic number, because the mean of its divisors is an integer number (3338271495988).
Almost surely, 213353002244121 is an apocalyptic number.
It is an amenable number.
13353002244121 is a deficient number, since it is larger than the sum of its proper divisors (83739831).
13353002244121 is an equidigital number, since it uses as much as digits as its factorization.
13353002244121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83739830.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13353002244121 its reverse (12144220035331), we get a palindrome (25497222279452).
The spelling of 13353002244121 in words is "thirteen trillion, three hundred fifty-three billion, two million, two hundred forty-four thousand, one hundred twenty-one".
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