Base | Representation |
---|---|
bin | 11110010111000111101110… |
… | …110001111011111111000001 |
3 | 122111210100220022112121101122 |
4 | 132113013232301323333001 |
5 | 120000224420022133010 |
6 | 1151554540345442025 |
7 | 40061145635345525 |
oct | 3627075661737701 |
9 | 574710808477348 |
10 | 133530244333505 |
11 | 39601949888848 |
12 | 12b870807a0315 |
13 | 5967b04105386 |
14 | 24d8c80d65d85 |
15 | 1068664c0e855 |
hex | 7971eec7bfc1 |
133530244333505 has 4 divisors (see below), whose sum is σ = 160236293200212. Its totient is φ = 106824195466800.
The previous prime is 133530244333489. The next prime is 133530244333561. The reversal of 133530244333505 is 505333442035331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 69858637989904 + 63671606343601 = 8358148^2 + 7979449^2 .
It is not a de Polignac number, because 133530244333505 - 24 = 133530244333489 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13353024433346 + ... + 13353024433355.
It is an arithmetic number, because the mean of its divisors is an integer number (40059073300053).
Almost surely, 2133530244333505 is an apocalyptic number.
It is an amenable number.
133530244333505 is a deficient number, since it is larger than the sum of its proper divisors (26706048866707).
133530244333505 is an equidigital number, since it uses as much as digits as its factorization.
133530244333505 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26706048866706.
The product of its (nonzero) digits is 2916000, while the sum is 44.
Adding to 133530244333505 its reverse (505333442035331), we get a palindrome (638863686368836).
The spelling of 133530244333505 in words is "one hundred thirty-three trillion, five hundred thirty billion, two hundred forty-four million, three hundred thirty-three thousand, five hundred five".
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