Base | Representation |
---|---|
bin | 11110010111001000110000… |
… | …110001111111110111010011 |
3 | 122111210110202111010220002121 |
4 | 132113020300301333313103 |
5 | 120000234202010130101 |
6 | 1151555242303155111 |
7 | 40061215242345031 |
oct | 3627106061776723 |
9 | 574713674126077 |
10 | 133531351645651 |
11 | 39602367937853 |
12 | 12b8732b5a5a97 |
13 | 5967c4c64636b |
14 | 24d8d48049551 |
15 | 10686cc03c0a1 |
hex | 797230c7fdd3 |
133531351645651 has 4 divisors (see below), whose sum is σ = 134853444236304. Its totient is φ = 132209259055000.
The previous prime is 133531351645613. The next prime is 133531351645661. The reversal of 133531351645651 is 156546153135331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133531351645651 - 211 = 133531351643603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133531351645661) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 661046295175 + ... + 661046295376.
It is an arithmetic number, because the mean of its divisors is an integer number (33713361059076).
Almost surely, 2133531351645651 is an apocalyptic number.
133531351645651 is a deficient number, since it is larger than the sum of its proper divisors (1322092590653).
133531351645651 is a wasteful number, since it uses less digits than its factorization.
133531351645651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1322092590652.
The product of its digits is 7290000, while the sum is 52.
The spelling of 133531351645651 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, three hundred fifty-one million, six hundred forty-five thousand, six hundred fifty-one".
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