13353500320051 has 4 divisors (see below), whose sum is σ = 13934087290512. Its totient is φ = 12772913349592.

The previous prime is 13353500320049. The next prime is 13353500320073. The reversal of 13353500320051 is 15002300535331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13353500320051 - 2¹ = 13353500320049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13353500319995 and 13353500320022.

It is not an unprimeable number, because it can be changed into a prime (13353500320001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290293485196 + ... + 290293485241.

It is an arithmetic number, because the mean of its divisors is an integer number (3483521822628).

Almost surely, 2^{13353500320051} is an apocalyptic number.

13353500320051 is a deficient number, since it is larger than the sum of its proper divisors (580586970461).

13353500320051 is an equidigital number, since it uses as much as digits as its factorization.

13353500320051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 580586970460.

The product of its (nonzero) digits is 20250, while the sum is 31.

Adding to 13353500320051 its reverse (15002300535331), we get a palindrome (28355800855382).

The spelling of 13353500320051 in words is "thirteen trillion, three hundred fifty-three billion, five hundred million, three hundred twenty thousand, fifty-one".