Base | Representation |
---|---|
bin | 1100001001010001101100… |
… | …0000111101110110011001 |
3 | 1202021120201211110111122010 |
4 | 3002110123000331312121 |
5 | 3222240440134431213 |
6 | 44222303301020133 |
7 | 2545521224655003 |
oct | 302243300756631 |
9 | 52246654414563 |
10 | 13353506561433 |
11 | 42892103685a5 |
12 | 15b7bba3b4649 |
13 | 75b2cbb7ca5c |
14 | 342455483373 |
15 | 18254e491ac3 |
hex | c251b03dd99 |
13353506561433 has 4 divisors (see below), whose sum is σ = 17804675415248. Its totient is φ = 8902337707620.
The previous prime is 13353506561429. The next prime is 13353506561443. The reversal of 13353506561433 is 33416560535331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13353506561433 - 22 = 13353506561429 is a prime.
It is a super-2 number, since 2×133535065614332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13353506561443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225584426903 + ... + 2225584426908.
It is an arithmetic number, because the mean of its divisors is an integer number (4451168853812).
Almost surely, 213353506561433 is an apocalyptic number.
It is an amenable number.
13353506561433 is a deficient number, since it is larger than the sum of its proper divisors (4451168853815).
13353506561433 is an equidigital number, since it uses as much as digits as its factorization.
13353506561433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4451168853814.
The product of its (nonzero) digits is 4374000, while the sum is 48.
The spelling of 13353506561433 in words is "thirteen trillion, three hundred fifty-three billion, five hundred six million, five hundred sixty-one thousand, four hundred thirty-three".
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