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133542035 = 5112428037
BaseRepresentation
bin1111111010110…
…11000010010011
3100022021122020022
413331123002103
5233141321120
621130134055
73211042244
oct775330223
9308248208
10133542035
1169421120
123888132b
1321888a73
1413a42ccb
15bacd025
hex7f5b093

133542035 has 8 divisors (see below), whose sum is σ = 174818736. Its totient is φ = 97121440.

The previous prime is 133542007. The next prime is 133542041. The reversal of 133542035 is 530245331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133542035 - 26 = 133541971 is a prime.

It is a super-2 number, since 2×1335420352 = 35666950223882450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133541995 and 133542013.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1213964 + ... + 1214073.

It is an arithmetic number, because the mean of its divisors is an integer number (21852342).

Almost surely, 2133542035 is an apocalyptic number.

133542035 is a deficient number, since it is larger than the sum of its proper divisors (41276701).

133542035 is a wasteful number, since it uses less digits than its factorization.

133542035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2428053.

The product of its (nonzero) digits is 5400, while the sum is 26.

The square root of 133542035 is about 11556.0388974769. The cubic root of 133542035 is about 511.1393660691.

Adding to 133542035 its reverse (530245331), we get a palindrome (663787366).

The spelling of 133542035 in words is "one hundred thirty-three million, five hundred forty-two thousand, thirty-five".

Divisors: 1 5 11 55 2428037 12140185 26708407 133542035