133542121153 has 4 divisors (see below), whose sum is σ = 152619567040. Its totient is φ = 114464675268.

The previous prime is 133542121121. The next prime is 133542121201. The reversal of 133542121153 is 351121245331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351121245331 = 677 ⋅518642903.

It is a cyclic number.

It is not a de Polignac number, because 133542121153 - 2⁵ = 133542121121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133542121103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9538722933 + ... + 9538722946.

It is an arithmetic number, because the mean of its divisors is an integer number (38154891760).

Almost surely, 2^133542121153 is an apocalyptic number.

It is an amenable number.

133542121153 is a deficient number, since it is larger than the sum of its proper divisors (19077445887).

133542121153 is an equidigital number, since it uses as much as digits as its factorization.

133542121153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19077445886.

The product of its digits is 10800, while the sum is 31.

Adding to 133542121153 its reverse (351121245331), we get a palindrome (484663366484).

The spelling of 133542121153 in words is "one hundred thirty-three billion, five hundred forty-two million, one hundred twenty-one thousand, one hundred fifty-three".