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13354771093435 = 52670954218687
BaseRepresentation
bin1100001001010110011001…
…1000110001011110111011
31202021200222221220101102201
43002111212120301132323
53222301032344442220
644223032552211031
72545564451214142
oct302254630613673
952250887811381
1013354771093435
1142897aa140172
1215b82b1999a77
1375b470b49c45
143425353b0759
151825c54c7d0a
hexc25666317bb

13354771093435 has 4 divisors (see below), whose sum is σ = 16025725312128. Its totient is φ = 10683816874744.

The previous prime is 13354771093409. The next prime is 13354771093441. The reversal of 13354771093435 is 53439017745331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13354771093435 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335477109339 + ... + 1335477109348.

It is an arithmetic number, because the mean of its divisors is an integer number (4006431328032).

Almost surely, 213354771093435 is an apocalyptic number.

13354771093435 is a deficient number, since it is larger than the sum of its proper divisors (2670954218693).

13354771093435 is an equidigital number, since it uses as much as digits as its factorization.

13354771093435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2670954218692.

The product of its (nonzero) digits is 14288400, while the sum is 55.

The spelling of 13354771093435 in words is "thirteen trillion, three hundred fifty-four billion, seven hundred seventy-one million, ninety-three thousand, four hundred thirty-five".

Divisors: 1 5 2670954218687 13354771093435