Base | Representation |
---|---|
bin | 1100001001010110011001… |
… | …1000110001011110111011 |
3 | 1202021200222221220101102201 |
4 | 3002111212120301132323 |
5 | 3222301032344442220 |
6 | 44223032552211031 |
7 | 2545564451214142 |
oct | 302254630613673 |
9 | 52250887811381 |
10 | 13354771093435 |
11 | 42897aa140172 |
12 | 15b82b1999a77 |
13 | 75b470b49c45 |
14 | 3425353b0759 |
15 | 1825c54c7d0a |
hex | c25666317bb |
13354771093435 has 4 divisors (see below), whose sum is σ = 16025725312128. Its totient is φ = 10683816874744.
The previous prime is 13354771093409. The next prime is 13354771093441. The reversal of 13354771093435 is 53439017745331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13354771093435 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1335477109339 + ... + 1335477109348.
It is an arithmetic number, because the mean of its divisors is an integer number (4006431328032).
Almost surely, 213354771093435 is an apocalyptic number.
13354771093435 is a deficient number, since it is larger than the sum of its proper divisors (2670954218693).
13354771093435 is an equidigital number, since it uses as much as digits as its factorization.
13354771093435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2670954218692.
The product of its (nonzero) digits is 14288400, while the sum is 55.
The spelling of 13354771093435 in words is "thirteen trillion, three hundred fifty-four billion, seven hundred seventy-one million, ninety-three thousand, four hundred thirty-five".
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