Base | Representation |
---|---|
bin | 10011011011110001100… |
… | …101010000101100000001 |
3 | 11201200010210120112122211 |
4 | 103123301211100230001 |
5 | 133340042143012442 |
6 | 2501303400302121 |
7 | 165325521451234 |
oct | 23336145205401 |
9 | 4650123515584 |
10 | 1335492938497 |
11 | 475419a47213 |
12 | 1969b1a71941 |
13 | 98c2349ccb3 |
14 | 488d132d41b |
15 | 24b14dc6617 |
hex | 136f1950b01 |
1335492938497 has 4 divisors (see below), whose sum is σ = 1341324785620. Its totient is φ = 1329661091376.
The previous prime is 1335492938489. The next prime is 1335492938573. The reversal of 1335492938497 is 7948392945331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1248316832961 + 87176105536 = 1117281^2 + 295256^2 .
It is a cyclic number.
It is not a de Polignac number, because 1335492938497 - 23 = 1335492938489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1335492936497) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2915923218 + ... + 2915923675.
It is an arithmetic number, because the mean of its divisors is an integer number (335331196405).
Almost surely, 21335492938497 is an apocalyptic number.
It is an amenable number.
1335492938497 is a deficient number, since it is larger than the sum of its proper divisors (5831847123).
1335492938497 is an equidigital number, since it uses as much as digits as its factorization.
1335492938497 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5831847122.
The product of its digits is 176359680, while the sum is 67.
The spelling of 1335492938497 in words is "one trillion, three hundred thirty-five billion, four hundred ninety-two million, nine hundred thirty-eight thousand, four hundred ninety-seven".
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