Base | Representation |
---|---|
bin | 1100001001010111010111… |
… | …1101001111110101111011 |
3 | 1202021201200011102201121020 |
4 | 3002111311331033311323 |
5 | 3222302101233010321 |
6 | 44223114523113523 |
7 | 2545604102435631 |
oct | 302256575176573 |
9 | 52251604381536 |
10 | 13355032313211 |
11 | 4289923637486 |
12 | 15b83653728a3 |
13 | 75b4b2cba464 |
14 | 34255bd6b351 |
15 | 1825dd3c64c6 |
hex | c2575f4fd7b |
13355032313211 has 4 divisors (see below), whose sum is σ = 17806709750952. Its totient is φ = 8903354875472.
The previous prime is 13355032313197. The next prime is 13355032313213. The reversal of 13355032313211 is 11231323055331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13355032313211 - 217 = 13355032182139 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13355032313213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225838718866 + ... + 2225838718871.
It is an arithmetic number, because the mean of its divisors is an integer number (4451677437738).
Almost surely, 213355032313211 is an apocalyptic number.
13355032313211 is a deficient number, since it is larger than the sum of its proper divisors (4451677437741).
13355032313211 is an equidigital number, since it uses as much as digits as its factorization.
13355032313211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4451677437740.
The product of its (nonzero) digits is 24300, while the sum is 33.
Adding to 13355032313211 its reverse (11231323055331), we get a palindrome (24586355368542).
The spelling of 13355032313211 in words is "thirteen trillion, three hundred fifty-five billion, thirty-two million, three hundred thirteen thousand, two hundred eleven".
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