Base | Representation |
---|---|
bin | 11000111000000010… |
… | …11101101111111011 |
3 | 1021110201212201122212 |
4 | 30130001131233323 |
5 | 204322343013211 |
6 | 10045113005335 |
7 | 651644014541 |
oct | 143401355773 |
9 | 37421781585 |
10 | 13355047931 |
11 | 57336381a5 |
12 | 27086b384b |
13 | 134ab04734 |
14 | 90998bd91 |
15 | 5326d638b |
hex | 31c05dbfb |
13355047931 has 4 divisors (see below), whose sum is σ = 13356612864. Its totient is φ = 13353483000.
The previous prime is 13355047913. The next prime is 13355047933. The reversal of 13355047931 is 13974055331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13974055331 = 953 ⋅14663227.
It is a cyclic number.
It is not a de Polignac number, because 13355047931 - 210 = 13355046907 is a prime.
It is a super-2 number, since 2×133550479312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13355047933) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 769595 + ... + 786756.
It is an arithmetic number, because the mean of its divisors is an integer number (3339153216).
Almost surely, 213355047931 is an apocalyptic number.
13355047931 is a deficient number, since it is larger than the sum of its proper divisors (1564933).
13355047931 is an equidigital number, since it uses as much as digits as its factorization.
13355047931 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1564932.
The product of its (nonzero) digits is 170100, while the sum is 41.
The spelling of 13355047931 in words is "thirteen billion, three hundred fifty-five million, forty-seven thousand, nine hundred thirty-one".
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